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Proof step 46 from proof int2bytes-rec-pos (previous step)

0 ≤ i % 256 ∧ i % 256 ≤ 127, uint2bits(i) = uint2bits(i / 256) + fillsgn(9, uint2bits(i % 256)).rest, # uint2bits(i % 256) ≤ 9, 255 < i, 0 < i, 0 ≤ i, i % 256 ≤ 127 ⊦ fillsgn(9, uint2bits(i % 256)) = [], i2b(bits2int(fillsgn(9, uint2bits(i % 256)).rest)) = i2b(i % 256) '.last

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 47:
uint2bits(i) = uint2bits(i / 256) + fillsgn(9, uint2bits(i % 256)).rest, # uint2bits(i % 256) ≤ 9, 255 < i, 0 < i, 0 ≤ i, i % 256 ≤ 127 ⊦ fillsgn(9, uint2bits(i % 256)) = [], i2b(bits2int(fillsgn(9, uint2bits(i % 256)).rest)) = i2b(i % 256), bits2int(fillsgn(9, uint2bits(i % 256)).rest) = i % 256

Rule argument

Additional information

Used simplifier rules: ⊦ i2b(i) ≠ i2b(j) → i ≠ j; (forward)% ⊦ 0 < j ∧ 0 ≤ i → 0 ≤ i % j;% ⊦ by '.last = by;