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Proof step 1 from proof int2bytes-rec255-neg (conclusion)

⊦ i < ~ 128 → int2bytes(i) = int2bytes((i - 255) / 256) + int2bytes(i % 256).last '

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 2:
i < ~128, i < 0 ⊦ int2bytes(i) = int2bytes((i - 255) / 256) + int2bytes(i % 256).last '

Rule argument

Additional information

Used simplifier rules: ⊦ i < (* j) ∧ j < 0 → i < 0; (forward)