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Proof step 20 from proof int2bytes-rec255-neg (previous step)

# int2bytes(i % 256) < 2, i < 0, i < ~128, i % 256 < 0 ⊦ ¬ ~128 ≤ i % 256, (mklist(i2b(~1), 2 - # int2bytes(i % 256)) + int2bytes(i % 256)).rest = int2bytes(i % 256).last '

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 21:
~128 ≤ i % 256, # int2bytes(i % 256) < 2, i < 0, i < ~128, i % 256 < 0, i < i % 256 ⊦ (mklist(i2b(~1), 2 - # int2bytes(i % 256)) + int2bytes(i % 256)).rest = int2bytes(i % 256).last '

Rule argument

Additional information

Used simplifier rules: ⊦ i ≤ j ∧ j < j0 → i < j0; (forward)% ⊦ i < j ∧ j ≤ j0 → i < j0; (forward)