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Proof step 29 from proof int2bytes-rec255-neg (previous step)

¬(~256 ≤ i % 256 ∧ i % 256 < ~128), i < 0, i < ~128, 2 < # int2bytes(i % 256) ⊦ lastn(2, int2bytes(i % 256)).rest = int2bytes(i % 256).last ', 2 = # int2bytes(i % 256)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 30:
i < 0, i < ~128, 2 < # int2bytes(i % 256) ⊦ lastn(2, int2bytes(i % 256)).rest = int2bytes(i % 256).last ', 2 = # int2bytes(i % 256), ¬ i % 256 < ~256 ∧ ¬ ~128 ≤ i % 256

Rule argument

Additional information

Used simplifier rules: ⊦ ¬ i < j ↔ j ≤ i;% ⊦ ¬ i ≤ j ↔ j < i;