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Proof step 31 from proof int2bytes-rec255-neg (previous step)

i < 0, i < ~128, 2 < # int2bytes(i % 256) ⊦ ¬ i % 256 < ~256, lastn(2, int2bytes(i % 256)).rest = int2bytes(i % 256).last ', 2 = # int2bytes(i % 256)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 32:
i % 256 < ~256, i < 0, i < ~128, 2 < # int2bytes(i % 256), i % 256 < 0 ⊦ lastn(2, int2bytes(i % 256)).rest = int2bytes(i % 256).last ', 2 = # int2bytes(i % 256)

Rule argument

Additional information

Used simplifier rules: ⊦ i < (* j) ∧ j < 0 → i < 0; (forward)