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Proof step 36 from proof int2bytes-rec255-neg (previous step)

i < 0, i < ~128, 2 < # int2bytes(i % 256) ⊦ ¬ ~128 ≤ i % 256, lastn(2, int2bytes(i % 256)).rest = int2bytes(i % 256).last ', 2 = # int2bytes(i % 256)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 37:
~128 ≤ i % 256, i < 0, i < ~128, 2 < # int2bytes(i % 256), i < i % 256 ⊦ lastn(2, int2bytes(i % 256)).rest = int2bytes(i % 256).last ', 2 = # int2bytes(i % 256)

Rule argument

Additional information

Used simplifier rules: ⊦ i < j ∧ j ≤ j0 → i < j0; (forward)