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Proof step 39 from proof int2bytes-rec255-neg (previous step)

2 = # int2bytes(i % 256), 2 ≤ # int2bytes(i % 256), i < 0, i < ~128 ⊦ int2bytes(i % 256).rest = int2bytes(i % 256).last '

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 40:
2 = # int2bytes(i % 256), i < ~128, i < 0 ⊦ int2bytes(i % 256).rest = int2bytes(i % 256).last '

Rule argument

Additional information

Used simplifier rules: 0 < n ⊦ (* n) ≤ m → m ≠ 0; (forward)