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Proof step 7 from proof int2bytes-rec255-neg (previous step)

¬ # int2bytes(i % 256) ≥ 2, i < ~128, i < 0 ⊦ fix(2, int2bytes(i % 256)).rest = int2bytes(i % 256).last '

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 8:
# int2bytes(i % 256) < 2, i < 0, i < ~128 ⊦ fix(2, int2bytes(i % 256)).rest = int2bytes(i % 256).last '

Rule argument

Additional information

Used simplifier rules: ⊦ m < n → n ≠ 0; (forward)% ⊦ ¬ m ≤ n ↔ n < m;% ⊦ n ≥ m ↔ m ≤ n;