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Proof step 10 from proof int2bytes-zero (previous step)

¬(~128 ≤ i ∧ i < 128), int2bytes(i) = i2b(0) ', i ≤ 127 ⊦ i = 0

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 11:
int2bytes(i) = i2b(0) ', i < 0, i < ~128 ⊦ i = 0

Rule argument

Additional information

Used simplifier rules: ⊦ i < 0 ∧ 0 ≤ j → i ≤ j;% ⊦ i < (* j) ∧ j < 0 → i < 0; (forward)%j0 ≠ 0, j < j0 ⊦ i ≤ (* j) → i < (* j0);% ⊦ ¬ i ≤ j ↔ j < i;