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Proof step 13 from proof int2bytes-zero (previous step)

~128 ≤ i ∧ i < 128, i2b(i) ' = i2b(0) ', i ≤ 127 ⊦ i = 0

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 14:
i2b(i) = i2b(0), ~128 ≤ i, i ≤ 127 ⊦ i = 0

Rule argument

Additional information

Used simplifier rules: ⊦ j ≤ j0 ∧ j0 ≤ j1 → j ≤ j1; (forward)%j0 ≠ 0, j < j0 ⊦ i ≤ (* j) → i < (* j0);% ⊦ by ' = by0 ' ↔ by = by0;