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Proof step 23 from proof no-leading-zero-01 (previous step)

i1 / 256 = 0, 0 ≤ b2i(int2bytes((i1 + 255) % 256).last), i1 < ~383, i1 < 0, ∀ bytes, by, i0. i→n(i0) < i→n(i1 + 255) → int2bytes(i0) = i2b(0) ' + by ' + bytes ∧ 0 ≤ b2i(by) ∧ i2b(0) ∈ int2bytes(i0) → false ⊦

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 24:
⊦ 0 ≠ j → (i / j = 0 ↔ abs(i) < abs(j))

Rule argument

seq: ⊦ 0 ≠ j → (i / j = 0 ↔ abs(i) < abs(j)) subst: [j, i] → [256, i1] rotate: F spec: int-div inst: name: div-eq-zero-01

Additional information

Used simplifier rules: ⊦ i < 0 → abs(i) = ~ i;% ⊦ ~ i < j ↔ 0 < j + i;% ⊦ (* j) < i0 + (* j0) ↔ j - j0 < i0;% ⊦ i < j ∧ ¬ i0 < j → ¬ i0 < i;% ⊦ i + j + i0 = (i + j) + i0;% ⊦ i + j = j + i; Used terms: 256, i1