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Proof step 51 from proof no-leading-zero-01 (previous step)

i1 < 0, 0 ≤ b2i(i2b(i1)), ~129 < i1, ∀ bytes, by, i0. i→n(i0) < i→n(i1 + 256) → int2bytes(i0) = i2b(0) ' + by ' + bytes ∧ 0 ≤ b2i(by) ∧ i2b(0) ∈ int2bytes(i0) → false ⊦

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 52:
⊦ ~128 ≤ i ∧ i ≤ 127 → b2i(i2b(i)) = i

Rule argument

seq: ⊦ ~128 ≤ i ∧ i ≤ 127 → b2i(i2b(i)) = i subst: [i] → [i1] rotate: F spec: byte inst: name: bib-in-01

Additional information

Used simplifier rules: i + 1 = i0 ⊦ j < (* i0) → ¬ (* i) < j;% ⊦ i < j ∧ ¬ i0 < j → ¬ i0 < i;% ⊦ ¬ i ≤ j ↔ j < i;%i0 ≠ 0, i0 ≤ i ⊦ (* i) ≤ j → (* i0) ≤ j;% ⊦ i < 0 ∧ 0 ≤ j → i ≤ j;% ⊦ i ≤ j → (¬ ¬ j < i ↔ false); Used terms: i1