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Proof step 1 from proof no-leading-zero-03 (conclusion)

⊦ 2 ≤ # bytes ∧ bytes.first = i2b(0) ∧ b2i(bytes.rest.first) < 0 → int2bytes(bytes2int(bytes)) = bytes

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 2:
bytes.first = i2b(0), b2i(bytes.rest.first) < 0, 2 ≤ # bytes ⊦ int2bytes(bytes2int(bytes)) = bytes, bytes = []

Rule argument

Additional information

Used simplifier rules: ⊦ # bytes = 0 ↔ bytes = [];%0 < n ⊦ (* n) ≤ m → m ≠ 0; (forward)% ⊦ j < i ∧ i ≤ 0 → j < 0; (forward)