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Proof step 13 from proof no-leading-zero-04 (previous step)

i / 256 = 0, i < ~256, i < 0, b2i(i2b(i % 256)) < 0, ∀ bytes, by, i0. i→n(i0) < i→n(i) → true → b2i(by) < 0 → int2bytes(i0) ≠ i2b(~1) ' + by ' + bytes ⊦ i % 256 = 0

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 14:
⊦ 0 ≠ j → (i / j = 0 ↔ abs(i) < abs(j))

Rule argument

seq: ⊦ 0 ≠ j → (i / j = 0 ↔ abs(i) < abs(j)) subst: [j, i] → [256, i] rotate: F spec: int-div inst: name: div-eq-zero-01

Additional information

Used simplifier rules: ⊦ i < 0 → abs(i) = ~ i;% ⊦ ~ i < j ↔ 0 < j + i;% ⊦ (* j) < i0 + (* j0) ↔ j - j0 < i0;% ⊦ i < j → ¬ j < i;% ⊦ i + j + i0 = (i + j) + i0;% ⊦ i + j = j + i; Used terms: 256, i