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Proof step 32 from proof no-leading-zero-04 (previous step)

b2i(by) < 0 → int2bytes(i / 256 - 1) ≠ i2b(~1) ' + by ' + bytes.butlast, int2bytes(i / 256 - 1) + i2b(i % 256) ' = i2b(~1) ' + by ' + bytes, i < 0, i < ~256, b2i(by) < 0, i2b(i % 256) ∈ bytes, ∀ bytes, by, i0. i→n(i0) < i→n(i) → true → b2i(by) < 0 → int2bytes(i0) ≠ i2b(~1) ' + by ' + bytes ⊦ bytes = [], i % 256 = 0, ¬ i2b(~1) ∈ int2bytes(i / 256 - 1) ∧ i2b(~1) ≠ i2b(i % 256)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 33:
int2bytes(i / 256 - 1) + i2b(i % 256) ' = i2b(~1) ' + by ' + bytes, i < 0, i < ~256, b2i(by) < 0, i2b(i % 256) ∈ bytes, ∀ bytes, by, i0. i→n(i0) < i→n(i) → true → b2i(by) < 0 → int2bytes(i0) ≠ i2b(~1) ' + by ' + bytes ⊦ bytes = [], i % 256 = 0, int2bytes(i / 256 - 1) = i2b(~1) ' + by ' + bytes.butlast, ¬ i2b(~1) ∈ int2bytes(i / 256 - 1) ∧ i2b(~1) ≠ i2b(i % 256)

Rule argument

Additional information

Used simplifier rules: ⊦ i < j → (¬ ¬ j ≤ i ↔ false);% ⊦ ¬ i < j ↔ j ≤ i;