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Proof step 5 from proof no-leading-zero-04 (previous step)

¬(i < ~256 ∧ i % 256 = 0), int2bytes(i) = i2b(~1) ' + by ' + bytes, b2i(by) < 0, i2b(~1) ∈ int2bytes(i), ∀ bytes, by, i0. i→n(i0) < i→n(i) → true → b2i(by) < 0 → int2bytes(i0) ≠ i2b(~1) ' + by ' + bytes ⊦

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 6:
int2bytes(i) = i2b(~1) ' + by ' + bytes, b2i(by) < 0, i2b(~1) ∈ int2bytes(i), ∀ bytes, by, i0. i→n(i0) < i→n(i) → true → b2i(by) < 0 → int2bytes(i0) ≠ i2b(~1) ' + by ' + bytes ⊦ ¬ ~256 ≤ i ∧ i % 256 = 0

Rule argument

Additional information

Used simplifier rules: ⊦ ¬ i < j ↔ j ≤ i;