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Proof step 3 from proof no-leading-zeros (previous step)

bytes.first = i2b(0) ∧ bytes.rest.first = i2b(0) ∧ int2bytes(bytes2int(bytes)) = bytes, ∀ bytes0. # bytes0 < # bytes → bytes0.first = i2b(0) ∧ bytes0.rest.first = i2b(0) ∧ int2bytes(bytes2int(bytes0)) = bytes0 → # bytes0 = 1 ∨ bytes0 = [] ⊦ # bytes = 1 ∨ bytes = []

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 4:
int2bytes(bytes2int(bytes)) = bytes, bytes.rest.first = i2b(0), bytes.first = i2b(0), ∀ bytes0. # bytes0 < # bytes → bytes0.first = i2b(0) ∧ bytes0.rest.first = i2b(0) ∧ int2bytes(bytes2int(bytes0)) = bytes0 → # bytes0 = 1 ∨ bytes0 = [] ⊦ bytes = [], # bytes = 1

Proof step 3 from proof no-leading-zeros (previous step)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Rule argument

Additional information