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Proof step 10 from proof rightshift-8-01-01 (previous step)

# int2bytes(i) ≤ i→n(j), 0 ≤ i ⊦ j = 0, i >> 8 * j = bytes2int(firstn(# int2bytes(i), mklist(i2b(0), (i→n(j) - # int2bytes(i)) + # int2bytes(i)) + int2bytes(i)))

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 11:
n ≤ m ⊦ (m - n) + n = m
Proof step 12:
# int2bytes(i) ≤ i→n(j), # int2bytes(i) ≤ i→n(j), 0 ≤ i ⊦ j = 0, i >> 8 * j = bytes2int(firstn(# int2bytes(i), mklist(i2b(0), i→n(j)) + int2bytes(i)))

Rule argument

seq: n ≤ m ⊦ (m - n) + n = m subst: [n, m] → [# int2bytes(i), i→n(j)] rotate: F spec: nat inst: name: prop-01

Additional information

Used terms: # int2bytes(i), i→n(j)