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Proof step 20 from proof rightshift-8-01-01 (previous step)

¬ abs(i) < abs(2 ^ (8 * abs(j))), 0 ≤ i, # int2bytes(i) ≤ i→n(j) ⊦ j = 0, i / 2 ^ (8 * abs(j)) = 0

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 21:
0 ≤ i, # int2bytes(i) ≤ i→n(j), 2 ^ (8 * abs(j)) ≤ i ⊦ j = 0, i / 2 ^ (8 * abs(j)) = 0

Rule argument

Additional information

Used simplifier rules: ⊦ ¬ i < j ↔ j ≤ i;% ⊦ abs(2 ^ i) = 2 ^ i;% ⊦ 0 ≤ i → abs(i) = i;