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Proof step 50 from proof rightshift-8-01-01 (previous step)

0 ≤ 2 ^ (8 * abs(j)) + i, i < 0, 2 ^ (8 * abs(j) - 1) + i < 0 ⊦ int2bytes(i).first = i2b(~1), i / 2 ^ (8 * abs(j)) = 0, j = 0, i % 2 ^ (8 * abs(j)) = 0

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 51:
abs(i) < abs(j) ⊦ i / j = 0
Proof step 52:
¬ abs(i) < abs(2 ^ (8 * abs(j))), 0 ≤ 2 ^ (8 * abs(j)) + i, i < 0, 2 ^ (8 * abs(j) - 1) + i < 0 ⊦ int2bytes(i).first = i2b(~1), i / 2 ^ (8 * abs(j)) = 0, j = 0, i % 2 ^ (8 * abs(j)) = 0

Rule argument

seq: abs(i) < abs(j) ⊦ i / j = 0 subst: [j, i] → [2 ^ (8 * abs(j)), i] rotate: F spec: int-div inst: name: div-zero-02

Additional information

Used terms: 2 ^ (8 * abs(j)), i