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Proof step 67 from proof rightshift-8-01-01 (previous step)

¬ 0 < j0, 0 ≤ 2 ^ (8 * abs(j)) * (j0 + 1), 2 ^ (8 * abs(j) - 1) + j0 * 2 ^ (8 * abs(j)) < 0, j0 * 2 ^ (8 * abs(j)) < 0 ⊦ j0 = ~1, int2bytes(j0 * 2 ^ (8 * abs(j))).first = i2b(~1), j = 0, 2 ^ (8 * abs(j)) = 0

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 68:
j0 < 0, 2 ^ (8 * abs(j) - 1) + j0 * 2 ^ (8 * abs(j)) < 0, 0 ≤ 2 ^ (8 * abs(j)) * (j0 + 1) ⊦ j0 = 0, 2 ^ (8 * abs(j)) = 0, j = 0, int2bytes(j0 * 2 ^ (8 * abs(j))).first = i2b(~1), j0 = ~1

Rule argument

Additional information

Used simplifier rules: ⊦ i < 0 ∧ 0 ≤ j → i < j;% ⊦ j < i ∧ i ≤ 0 → j < 0; (forward)% ⊦ i < j ∧ j ≤ j0 → i < j0; (forward)% ⊦ i ≠ j → (i ≤ j ↔ i < j);% ⊦ i * j * j0 = (i * j) * j0;% ⊦ 0 ≤ abs(i);% ⊦ 0 < i → (0 ≤ i * j ↔ 0 ≤ j);% ⊦ 0 < 2 ^ i ↔ 0 ≤ i;% ⊦ i ≤ 0 → (i * j < 0 ↔ ¬ ¬(0 < j ∧ i ≠ 0));% ⊦ ¬ i < j ↔ j ≤ i;% ⊦ i * j = j * i;