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Proof step 85 from proof rightshift-8-01-01 (previous step)

¬(0 ≤ b2i(firstn(# int2bytes(i) - i→n(j), int2bytes(i)).first) ∧ firstn(# int2bytes(i) - i→n(j), int2bytes(i)) ≠ []), i→n(j) < # int2bytes(i), 0 ≤ i ⊦ j = 0, bytes2int(firstn(# int2bytes(i) - i→n(j), int2bytes(i))) = bytes2int(mklist(i2b(0), i→n(j)) + firstn(# int2bytes(i) - i→n(j), int2bytes(i)))

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Rule argument

Additional information

Used simplifier rules: ⊦ i < 0 ∧ 0 ≤ j → i < j;% ⊦ j < i ∧ i ≤ 0 → j < 0; (forward)% ⊦ i < j ∧ j ≤ j0 → i < j0; (forward)% ⊦ n < m → m - n ≠ 0;% ⊦ firstn(n, bytes) = [] ↔ n = 0;% ⊦ ¬ i ≤ j ↔ j < i;