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Proof step 2 from proof rightshift-8-01 (previous step)

i→n(j) < # int2bytes(i) ⊦ i >> 8 * j = bytes2int(firstn(# int2bytes(i) - i→n(j), int2bytes(i)))

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 3:
⊦ i >> j = i >> abs(j)
Proof step 4:
i→n(j) < # int2bytes(i) ⊦ i >> abs(8 * j) = bytes2int(firstn(# int2bytes(i) - i→n(j), int2bytes(i)))

Rule argument

seq: ⊦ i >> j = i >> abs(j) subst: [j, i] → [8 * j, i] rotate: F spec: intops inst: name: shiftright-abs

Additional information

Used terms: 8 * j, i