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Proof step 39 from proof rightshift-8-01 (previous step)

i < 0, i < ~256, i→n(j) ≤ # int2bytes(i / 256 - 1), abs(j) ≤ abs(abs(j) - 1), ∀ i, j0. i→n(j0) < i→n(j) → i→n(j0) < # int2bytes(i) → i >> 8 * abs(j0) = bytes2int(firstn(# int2bytes(i) - i→n(j0), int2bytes(i))) ⊦ i % 256 = 0, j = 0, (i / 256 - 1) >> 8 * (abs(j) - 1) = bytes2int(firstn((# int2bytes(i / 256 - 1) - i→n(j)) + 1, int2bytes(i / 256 - 1) + i2b(i % 256) '))

User applied rule insert rewrite lemma

And obtained the following new goals

Rule argument

seq: ⊦ ¬ j < 0 → abs(j) = j subst: [j] → [abs(j) - 1] rotate: F spec: int-abs inst: name: Abs-pos

Additional information

Used simplifier rules: ⊦ abs(i) - 1 < 0 ↔ i = 0;% ⊦ i ≤ j - i0 ↔ i + i0 ≤ j;% ⊦ i + j ≤ i ↔ j ≤ 0;% ⊦ i + j + i0 = (i + j) + i0;% ⊦ i + j = j + i; Used terms: abs(j) - 1