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Proof step 5 from proof rightshift-8-01 (previous step)

i→n(j) < # int2bytes(i) ⊦ i >> 8 * abs(j) = bytes2int(firstn(# int2bytes(i) - i→n(j), int2bytes(i)))

User applied rule induction

And obtained the following new goals

Proof step 6:
i→n(j) < # int2bytes(i), ∀ i, j0. i→n(j0) < i→n(j) → i→n(j0) < # int2bytes(i) → i >> 8 * abs(j0) = bytes2int(firstn(# int2bytes(i) - i→n(j0), int2bytes(i))) ⊦ i >> 8 * abs(j) = bytes2int(firstn(# int2bytes(i) - i→n(j), int2bytes(i)))

Rule argument

indvar: i→n(j) wfpred: <

Additional information

Used simplifier rules: <; (wellfounded) Used terms: i→n(j)