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Proof step 64 from proof rightshift-8-01 (previous step)

¬(~256 < i ∧ i < ~128), i % 256 = 0, i→n(j) < # int2bytes(i), i < 0, ~256 ≤ i, ~256 < i, ∀ i, j0. i→n(j0) < i→n(j) → i→n(j0) < # int2bytes(i) → i >> 8 * abs(j0) = bytes2int(firstn(# int2bytes(i) - i→n(j0), int2bytes(i))) ⊦ j = 0, 0 = bytes2int(firstn(# int2bytes(i) - i→n(j), int2bytes(i)))

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 65:
i % 256 = 0, i→n(j) < # int2bytes(i), i < 0, ~128 ≤ i, ∀ i, j0. i→n(j0) < i→n(j) → i→n(j0) < # int2bytes(i) → i >> 8 * abs(j0) = bytes2int(firstn(# int2bytes(i) - i→n(j0), int2bytes(i))) ⊦ j = 0, 0 = bytes2int(firstn(# int2bytes(i) - i→n(j), int2bytes(i)))

Rule argument

Additional information

Used simplifier rules: i0 ≠ 0, i0 < i ⊦ (* i) ≤ j → (* i0) < j;%i0 ≠ 0, i0 ≤ i ⊦ (* i) ≤ j → (* i0) ≤ j;% ⊦ ¬ i < j ↔ j ≤ i;%i0 ≠ 0, i0 ≤ i ⊦ (* i) < j → (* i0) < j;