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Proof step 72 from proof rightshift-8-01 (previous step)

i % 256 = 0, i→n(j) < 2, i < ~128, ~256 < i, ~256 ≤ i, i < 0, ∀ i, j0. i→n(j0) < i→n(j) → i→n(j0) < # int2bytes(i) → i >> 8 * abs(j0) = bytes2int(firstn(# int2bytes(i) - i→n(j0), int2bytes(i))) ⊦ j = 1, 0 = bytes2int(firstn(2 - i→n(j), i2b(~1) ' + i2b(i) ')), j = 0

User applied rule cut formula

And obtained the following new goals

Proof step 73:
i % 256 = 0, i→n(j) < 2, i < ~128, ~256 < i, ~256 ≤ i, i < 0, ∀ i, j0. i→n(j0) < i→n(j) → i→n(j0) < # int2bytes(i) → i >> 8 * abs(j0) = bytes2int(firstn(# int2bytes(i) - i→n(j0), int2bytes(i))) ⊦ j = 1, j = 1, 0 = bytes2int(firstn(2 - i→n(j), i2b(~1) ' + i2b(i) ')), j = 0

Rule argument

fma: j = 1

Additional information

Used formulas: j = 1