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Proof step 9 from proof rightshift-8-01 (previous step)

i→n(j) < # int2bytes(i), i < 0, ∀ i, j0. i→n(j0) < i→n(j) → i→n(j0) < # int2bytes(i) → i >> 8 * abs(j0) = bytes2int(firstn(# int2bytes(i) - i→n(j0), int2bytes(i))) ⊦ i >> 8 * abs(j) = bytes2int(firstn(# int2bytes(i) - i→n(j), int2bytes(i))), j = 0

User applied rule insert rewrite lemma

And obtained the following new goals

Rule argument

seq: ⊦ i < 0 ∧ 8 ≤ j → i >> j = (i - 255) / 256 >> (j - 8) subst: [j, i] → [8 * abs(j), i] rotate: F spec: intops inst: name: shiftright-rec-8-neg

Additional information

Used simplifier rules: ⊦ ¬ i < j ↔ j ≤ i;% ⊦ i < j → (¬ ¬ j ≤ i ↔ false);% ⊦ 0 < i ∧ 0 ≤ j → ((* j) ≤ (* i) * i0 ↔ (i + j - 1) / i ≤ i0);% ⊦ 1 ≤ i ↔ 0 < i;% ⊦ 0 < abs(i) ↔ i ≠ 0;% ⊦ i * j * j0 = (i * j) * j0;% ⊦ i * j = j * i; Used terms: 8 * abs(j), i