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Proof step 17 from proof rightshift-8-02 (previous step)

int2bytes(i) = by + bytes ∧ int2bytes(i) ≠ [], int2bytes(i) = by ', 0 ≤ i ⊦ i >> 8 = bytes2int(i2b(0) ' + int2bytes(i).butlast)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Rule argument

Additional information

Used simplifier rules: int2bytes-empty: ⊦ int2bytes(i) ≠ [];%bytes2int-zero: ⊦ bytes2int(i2b(0) ') = 0;% ⊦ by ∈ by0 ' ↔ by = by0;% ⊦ bytes + [] = bytes;% ⊦ by '.butlast = [];% ⊦ by ' = by0 ' + bytes ↔ by = by0 ∧ bytes = [];% ⊦ (bytes + bytes0) + bytes1 = bytes + bytes0 + bytes1;% ⊦ by ' + bytes = bytes0 → by ∈ bytes0; (forward)% ⊦ by + bytes = by ' + bytes;