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Proof step 49 from proof rightshift-8-02 (previous step)

i % 2 ^ abs(8) ≠ 0 ∧ i < ~(2 ^ (abs(8) - 1)) ∧ 8 ≠ 0, int2bytes(i) = by ', i < 0, i < ~128, ~256 ≤ i ⊦ i / 2 ^ abs(8) - 1 = ~1, i % 256 = 0

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 50:
int2bytes(i) = by ', i < 0, ~256 ≤ i, i < ~128 ⊦ i / 256 = 0, i % 256 = 0

Rule argument

Additional information

Used simplifier rules: j0 ≠ 0, j ≤ j0 ⊦ i < (* j) → i < (* j0);% ⊦ i - j = i0 ↔ i = i0 + j;