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Proof step 2 from proof rightshift-8 (previous step)

⊦ i >> 8 = bytes2int(int2bytes(i).butlast), # int2bytes(i) = 1

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 3:
⊦ i < 0 ∧ 8 ≤ j → i >> j = (i - 255) / 256 >> (j - 8)
Proof step 4:
¬(i < 0 ∧ 8 ≤ 8) ⊦ i >> 8 = bytes2int(int2bytes(i).butlast), # int2bytes(i) = 1
Proof step 14:
i < 0 ∧ 8 ≤ 8 ⊦ (i - 255) / 256 >> (8 - 8) = bytes2int(int2bytes(i).butlast), # int2bytes(i) = 1

Rule argument

seq: ⊦ i < 0 ∧ 8 ≤ j → i >> j = (i - 255) / 256 >> (j - 8) subst: [j, i] → [8, i] rotate: F spec: intops inst: name: shiftright-rec-8-neg

Additional information

Used terms: 8, i