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Proof step 20 from proof rightshift-8 (previous step)

i % 256 = 0 ∧ i < 0, i % 256 = 0, i < 0 ⊦ # int2bytes(i) = 1, i / 256 = bytes2int(int2bytes(i).butlast)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Rule argument

Additional information