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Proof step 36 from proof rightshift-8 (previous step)

i < ~128, i < 0 ⊦ # (¬ i ≤ ~256 ⊃ i2b(~1) ' + i2b(i) ';(i ≠ ~256 ⊃ int2bytes(i / 256 - 1) + i2b(i % 256) ';i2b(~1) ' + i2b(0) ')) = 1, i % 256 = 0, i / 256 = bytes2int ((¬ i < ~128 ⊃ i2b(i) ';(¬ i ≤ ~256 ⊃ i2b(~1) ' + i2b(i) ';(i ≠ ~256 ⊃ int2bytes(i / 256 - 1) + i2b(i % 256) ';i2b(~1) ' + i2b(0) '))) .butlast) + 1

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 37:
i < ~128, i < 0 ⊦ # (¬ i ≤ ~256 ⊃ i2b(~1) ' + i2b(i) ';(i ≠ ~256 ⊃ int2bytes(i / 256 - 1) + i2b(i % 256) ';i2b(~1) ' + i2b(0) ')) = 1, i % 256 = 0, i / 256 = 1 + bytes2int((¬ i ≤ ~256 ⊃ i2b(~1) ' + i2b(i) ';(i ≠ ~256 ⊃ int2bytes(i / 256 - 1) + i2b(i % 256) ';i2b(~1) ' + i2b(0) ')).butlast)

Rule argument

Additional information

Used simplifier rules: j0 ≠ 0, j ≤ j0 ⊦ i < (* j) → i < (* j0);