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Proof step 5 from proof rightshift-8 (previous step)

0 ≤ i ⊦ i >> 8 = bytes2int(int2bytes(i).butlast), # int2bytes(i) = 1

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 6:
⊦ 0 ≤ i ∧ 8 ≤ j → i >> j = i / 256 >> (j - 8)
Proof step 7:
0 ≤ i ∧ 8 ≤ 8, 0 ≤ i ⊦ i / 256 >> (8 - 8) = bytes2int(int2bytes(i).butlast), # int2bytes(i) = 1

Rule argument

seq: ⊦ 0 ≤ i ∧ 8 ≤ j → i >> j = i / 256 >> (j - 8) subst: [j, i] → [8, i] rotate: F spec: intops inst: name: shiftright-rec-8

Additional information

Used simplifier rules: ⊦ ¬ i ≤ j ↔ j < i;% ⊦ i ≤ j → (¬ ¬ j < i ↔ false); Used terms: 8, i