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Proof step 127 from proof setInt-theorem (previous step)

b2i(i2b(i >> 16)) < 0, i >> 16 = b2i(i2b(i >> 16)), i >> 8 < ~128, i < ~128, i >> 8 < 0, i < 0 ⊦ i = b2i(i2b(i)), i2b(~1) = i2b(i >> 24)

User applied rule cut formula

And obtained the following new goals

Proof step 128:
i >> 24 = (i >> 16) >> 8, b2i(i2b(i >> 16)) < 0, i >> 16 = b2i(i2b(i >> 16)), i >> 8 < ~128, i < ~128, i >> 8 < 0, i < 0 ⊦ i = b2i(i2b(i)), i2b(~1) = i2b(i >> 24)
Proof step 129:
b2i(i2b(i >> 16)) < 0, i >> 16 = b2i(i2b(i >> 16)), i >> 8 < ~128, i < ~128, i >> 8 < 0, i < 0 ⊦ i >> 24 = (i >> 16) >> 8, i = b2i(i2b(i)), i2b(~1) = i2b(i >> 24)

Rule argument

fma: i >> 24 = (i >> 16) >> 8

Additional information

Used formulas: i >> 24 = (i >> 16) >> 8