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Proof step 13 from proof setInt-theorem (previous step)

# int2bytes(i) = 1, # int2bytes(i) ≤ 4, fillsgn(4, int2bytes(i)) = by ' + by0 ' + by1 ' + by2 ', by ∈ fillsgn(4, int2bytes(i)), by2 ∈ fillsgn(4, int2bytes(i)) ⊦ by = i2b(i >> 24) ∧ by0 = i2b(i >> 16) ∧ by1 = i2b(i >> 8) ∧ by2 = i2b(i)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Rule argument

Additional information

Used simplifier rules: int2bytes-len-one-01: ⊦ # int2bytes(i) = 1 ↔ int2bytes(i) = i2b(i) ';%int2bytes-len-one: ⊦ int2bytes(i) = by ' ↔ i = b2i(by);%b2i-i2b-same: ⊦ b2i(by) = i → by = i2b(i); (forward) from specification byte