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Proof step 137 from proof setInt-theorem (previous step)

# int2bytes(i) = 4, int2bytes(i) = by ' + by0 ' + by1 ' + by2 ', by2 ∈ int2bytes(i), by ∈ int2bytes(i) ⊦ i = b2i(i2b(i)), by = i2b(i >> 24) ∧ by0 = i2b(i >> 16) ∧ by1 = i2b(i >> 8) ∧ by2 = i2b(i)

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 138:
⊦ i < ~128 ∨ 128 ≤ i → int2bytes(i) = int2bytes(i >> 8) + i2b(i)
Proof step 139:
¬(i < ~128 ∨ 128 ≤ i), # int2bytes(i) = 4, int2bytes(i) = by ' + by0 ' + by1 ' + by2 ', by2 ∈ int2bytes(i), by ∈ int2bytes(i) ⊦ i = b2i(i2b(i)), by = i2b(i >> 24) ∧ by0 = i2b(i >> 16) ∧ by1 = i2b(i >> 8) ∧ by2 = i2b(i)
Proof step 142:
i < ~128 ∨ 128 ≤ i, #(int2bytes(i >> 8) + i2b(i)) = 4, int2bytes(i >> 8) + i2b(i) = by ' + by0 ' + by1 ' + by2 ', by2 ∈ int2bytes(i >> 8) + i2b(i), by ∈ int2bytes(i >> 8) + i2b(i) ⊦ i = b2i(i2b(i)), by = i2b(i >> 24) ∧ by0 = i2b(i >> 16) ∧ by1 = i2b(i >> 8) ∧ by2 = i2b(i)

Rule argument

spec: bytes inst: name: int2bytes-rec-shift seq: ⊦ i < ~128 ∨ 128 ≤ i → int2bytes(i) = int2bytes(i >> 8) + i2b(i) subst: [i] → [i] flags: rewrite, current

Additional information

Used terms: i