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Proof step 148 from proof setInt-theorem (previous step)

i >> 8 < ~128 ∨ 128 ≤ i >> 8, int2bytes((i >> 8) >> 8) + i2b(i >> 8) = by ' + by0 ' + by1 ', 3 = #(int2bytes((i >> 8) >> 8) + i2b(i >> 8)), by1 ∈ int2bytes((i >> 8) >> 8) + i2b(i >> 8), by ∈ int2bytes((i >> 8) >> 8) + i2b(i >> 8), i < ~128 ∨ 128 ≤ i ⊦ i = b2i(i2b(i)), by = i2b(i >> 24) ∧ by0 = i2b(i >> 16) ∧ by1 = i2b(i >> 8)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 149:
int2bytes((i >> 8) >> 8) = by ' + by0 ', i >> 8 < ~128 ∨ 128 ≤ i >> 8, i < ~128 ∨ 128 ≤ i ⊦ i = b2i(i2b(i)), by = i2b(i >> 24) ∧ by0 = i2b(i >> 16)

Rule argument

Additional information

Used simplifier rules: in-14: ⊦ by ' + bytes = bytes0 → by ∈ bytes0; (forward) from specification list[bytelist]%in-15: ⊦ bytes + by ' = bytes0 → by ∈ bytes0; (forward) from specification list[bytelist]%in-17: ⊦ by ∈ by0 ' ↔ by = by0; from specification list[bytelist]%in-append: ⊦ by ∈ bytes + bytes0 ↔ ¬ ¬(by ∈ bytes ∨ by ∈ bytes0); from specification list[bytelist]%c: ⊦ m + n = n + m; from specification nat-basic2%a: ⊦ (m + n0) + n1 = m + n0 + n1; from specification nat-basic2%add-num-04: n0 < n ⊦ (* n) = m0 + (* n0) ↔ n - n0 = m0; from specification nat%len-02: ⊦ # by ' = 0 +1; from specification list[bytelist]%len: ⊦ #(bytes + bytes0) = # bytes + # bytes0; from specification list[bytelist]%a: ⊦ (bytes + bytes0) + bytes1 = bytes + bytes0 + bytes1; from specification list[bytelist]%app-06: ⊦ bytes + by ' = bytes0 + by0 ' ↔ bytes = bytes0 ∧ by = by0; from specification list[bytelist]%Last: ⊦ bytes + by = bytes + by '; from specification list[bytelist]