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Proof step 25 from proof setInt-theorem (previous step)

0 ≤ b2i(i2b(i)) ⊦ i2b(0) = i2b(b2i(i2b(i)) >> 16) ∧ i2b(0) = i2b(b2i(i2b(i)) >> 24)

User applied rule insert rewrite lemma

And obtained the following new goals

Rule argument

spec: byte inst: name: shiftright-byte-8-pos-01 seq: ⊦ 0 ≤ b2i(by) ∧ 8 ≤ j → b2i(by) >> j = 0 subst: [j, by] → [16, i2b(i)] flags: rewrite

Additional information

Used simplifier rules: zero-gels-04: ⊦ i ≤ 0 ∧ 0 ≤ j → i ≤ j; from specification int-abs Used terms: 16, i2b(i)