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Proof step 36 from proof setInt-theorem (previous step)

b2i(i2b(i)) < 0 ∧ 8 ≤ 16, b2i(i2b(i)) < 0 ⊦ i2b(~1) = i2b(~1) ∧ i2b(~1) = i2b(b2i(i2b(i)) >> 24)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Rule argument

Additional information