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Proof step 63 from proof setInt-theorem (previous step)

i >> 8 = b2i(i2b(i >> 8)), i >> 24 = (i >> 8) >> 16, i >> 16 = (i >> 8) >> 8, 0 ≤ i >> 8, 128 ≤ i, 0 < i, 0 ≤ i ⊦ i = b2i(i2b(i)), i2b(0) = i2b(i >> 24) ∧ i2b(0) = i2b(i >> 16)

User applied rule insert equation

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Rule argument

pos: left 1 flags: discard

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