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Proof step 70 from proof setInt-theorem (previous step)

0 ≤ 8 ∧ 0 ≤ 8 ∧ 8 + 8 < 32, i >> 8 = b2i(i2b(i >> 8)), 0 ≤ i, 0 < i, 128 ≤ i, 0 ≤ i >> 8 ⊦ i >> 16 = i >> (8 + 8) ∧ i >> 24 = (i >> 8) >> 16, i = b2i(i2b(i)), i2b(0) = i2b(i >> 24) ∧ i2b(0) = i2b(i >> 16)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 71:
i >> 8 = b2i(i2b(i >> 8)), 0 ≤ i, 0 < i, 128 ≤ i, 0 ≤ i >> 8 ⊦ i = b2i(i2b(i)), i >> 24 = (i >> 8) >> 16, i2b(0) = i2b(i >> 24) ∧ i2b(0) = i2b(i >> 16)

Rule argument

Additional information

Used simplifier rules: add-c: ⊦ i + j = j + i; from specification int-basic2%add-a: ⊦ i + j + i0 = (i + j) + i0; from specification int-basic2