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Proof step 76 from proof setInt-theorem (previous step)

i >> 8 = b2i(i2b(i >> 8)), i >> 24 = (i >> 8) >> 16, i >> 16 = (i >> 8) >> 8, i < 0, i < ~128, i >> 8 < 0 ⊦ i = b2i(i2b(i)), i2b(~1) = i2b(i >> 24) ∧ i2b(~1) = i2b(i >> 16)

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Rule argument

pos: left 1 flags: discard

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