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Proof step 95 from proof setInt-theorem (previous step)

i < ~128 ∨ 128 ≤ i, #(int2bytes(i >> 8) + i2b(i)) = 3, fillsgn(3, int2bytes(i >> 8)) = by ' + by0 ' + by1 ' ⊦ i = b2i(i2b(i)), by = i2b(i >> 24) ∧ by0 = i2b(i >> 16) ∧ by1 = i2b(i >> 8)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 96:
fillsgn(3, int2bytes(i >> 8)) = by ' + by0 ' + by1 ', 2 = # int2bytes(i >> 8), i < ~128 ∨ 128 ≤ i ⊦ i = b2i(i2b(i)), by = i2b(i >> 24) ∧ by0 = i2b(i >> 16) ∧ by1 = i2b(i >> 8)

Rule argument

Additional information

Used simplifier rules: c: ⊦ m + n = n + m; from specification nat-basic2%a: ⊦ (m + n0) + n1 = m + n0 + n1; from specification nat-basic2%add-num-04: n0 < n ⊦ (* n) = m0 + (* n0) ↔ n - n0 = m0; from specification nat%a: ⊦ (bytes + bytes0) + bytes1 = bytes + bytes0 + bytes1; from specification list[bytelist]%len-02: ⊦ # by ' = 0 +1; from specification list[bytelist]%len: ⊦ #(bytes + bytes0) = # bytes + # bytes0; from specification list[bytelist]%Last: ⊦ bytes + by = bytes + by '; from specification list[bytelist]