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Proof step 98 from proof setInt-theorem (previous step)

¬(# int2bytes(i >> 8) < 3 ∧ bytes2int(int2bytes(i >> 8)) < 0), fillsgn(3, int2bytes(i >> 8)) = by ' + by0 ' + by1 ', 2 = # int2bytes(i >> 8), i < ~128 ∨ 128 ≤ i ⊦ i = b2i(i2b(i)), by = i2b(i >> 24) ∧ by0 = i2b(i >> 16) ∧ by1 = i2b(i >> 8)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Rule argument

Additional information

Used simplifier rules: int2int: ⊦ bytes2int(int2bytes(i)) = i;%forward-le: ⊦ i ≤ j ∧ 0 < i → 0 < j; (forward) from specification int-abs%numleledel-01: i0 ≠ 0, i0 ≤ i ⊦ (* i) ≤ j → (* i0) ≤ j; from specification int-abs%shiftright-not-pos-01: ⊦ i < 0 → ¬ 0 ≤ i >> j; from specification intops%numlsf: ⊦ i < (* j) ∧ j < 0 → i < 0; (forward) from specification int-basic1%forward-le-01: ⊦ i ≤ j ∧ 0 ≤ i → 0 ≤ j; (forward) from specification int-abs%lels: ⊦ ¬ i < j ↔ j ≤ i; from specification int-abs