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Proof step 12 from proof setShort-theorem-01 (previous step)

fillsgn(2, int2bytes(s2i(sho))) = by ' + bytes, bytes = bytes.first ' ⊦ by ' + bytes = i2b(s2i(sho) i>> 8) ' + i2b(s2i(sho)) ', bytes = []

Heuristic elimination applied rule insert elim lemma

And obtained the following new goals

Rule argument

spec: list-data inst: bytelist name: elim-list-c seq: bytes ≠ [] ⊦ by = bytes.first ∧ bytes0 = bytes.rest ↔ bytes = by + bytes0 subst: [bytes, by, bytes0] → [bytes, by0, bytes0] flags:

Additional information

Used simplifier rules: bytes ≠ [] ⊦ by = bytes.first ∧ bytes0 = bytes.rest ↔ bytes = by + bytes0; (elim) Used terms: bytes, by0, bytes0