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Proof step 15 from proof setShort-theorem-01 (previous step)

⊦ ¬(by0 = i2b(s2i(sho)) ∧ by = i2b(s2i(sho) i>> 8)) → fillsgn(2, int2bytes(s2i(sho))) ≠ by ' + by0 '

Lemma setShort-theorem