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Proof step 21 from proof setShort-theorem (previous step)

fillsgn(1, int2bytes(s2i(sho) >> 8)) = by ', # int2bytes(s2i(sho)) ≤ 2 ⊦ by = i2b(s2i(sho) >> 8), s2i(sho) = b2i(i2b(s2i(sho)))

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 22:
⊦ # bytes ≥ n → fillsgn(n, bytes) = bytes

Rule argument

name: fillsgn-longer rotate: F subst: [bytes, n] → [int2bytes(s2i(sho) >> 8), 1]

Additional information

Used simplifier rules: int2bytes-empty: ⊦ int2bytes(i) ≠ [];%int2bytes-len-one: ⊦ int2bytes(i) = by ' ↔ i = b2i(by);% ⊦ b2i(by) = i → (i2b(i) ≠ by ↔ false);% ⊦ n ≥ m ↔ m ≤ n;% ⊦ ¬ m ≤ n ↔ n < m;% ⊦ m < 1 ↔ m = 0;% ⊦ # bytes = 0 ↔ bytes = []; Used terms: int2bytes(s2i(sho) >> 8), 1