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Proof step 1 from proof short-2bytes-01 (conclusion)

⊦ ¬ 65536 ≤ bytes2int(by ' + by0 ') + s2i(sho)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 2:
65536 ≤ bytes2int(by ' + by0 ') + s2i(sho), 0 < bytes2int(by ' + by0 ') + s2i(sho), 0 ≤ bytes2int(by ' + by0 ') + s2i(sho) ⊦

Rule argument

Additional information

Used simplifier rules: ⊦ i ≤ j ∧ 0 < i → 0 < j; (forward)% ⊦ i ≤ j ∧ 0 ≤ i → 0 ≤ j; (forward)