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Proof step 1 from proof short-2bytes-02 (conclusion)

⊦ 0 ≤ i → ¬ 32768 + i < bytes2int(by ' + by0 ')

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 2:
32768 + i < bytes2int(by ' + by0 '), 0 ≤ i ⊦

Rule argument

Additional information

Used simplifier rules: ⊦ i ≤ j ∧ 0 ≤ i → 0 ≤ j; (forward)